Make s the subject of the relation P S frac sm ... - WAEC Mathematics 2016 Question
Make s the subject of the relation: P = S + (\frac{sm^2}{nr})
A
s = \(\frac{mrp}{nr + m^2}\)
B
s = \(\frac{nr + m^2}{mrp}\)
C
s = \(\frac{nrp}{mr + m^2}\)
D
s = \(\frac{nrp}{nr + m^2}\)
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Correct Option: D
P = S + (\frac{sm^2}{nr})
P = S(1 + (\frac{m^2}{nr}))
P = S(1 + (\frac{nr + m^2}{nr}))
nrp = S(nr + m2)
S = (\frac{nrp}{nr + m^2})
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